SQLite3Stmt::bindValue

(PHP 5 >= 5.3.0, PHP 7, PHP 8)

SQLite3Stmt::bindValueBinds the value of a parameter to a statement variable

说明

public SQLite3Stmt::bindValue ( string|int $param , mixed $value , int $type = SQLITE3_TEXT ) : bool

Binds the value of a parameter to a statement variable.

Caution

Before PHP 7.2.14 and 7.3.0, respectively, once the statement has been executed, SQLite3Stmt::reset() needs to be called to be able to change the value of bound parameters.

参数

param

Either a string (for named parameters) or an int (for positional parameters) identifying the statement variable to which the value should be bound. If a named parameter does not start with a colon (:) or an at sign (@), a colon (:) is automatically preprended. Positional parameters start with 1.

value

The value to bind to a statement variable.

type

The data type of the value to bind.

  • SQLITE3_INTEGER: The value is a signed integer, stored in 1, 2, 3, 4, 6, or 8 bytes depending on the magnitude of the value.

  • SQLITE3_FLOAT: The value is a floating point value, stored as an 8-byte IEEE floating point number.

  • SQLITE3_TEXT: The value is a text string, stored using the database encoding (UTF-8, UTF-16BE or UTF-16-LE).

  • SQLITE3_BLOB: The value is a blob of data, stored exactly as it was input.

  • SQLITE3_NULL: The value is a NULL value.

As of PHP 7.0.7, if type is omitted, it is automatically detected from the type of the value: bool and int are treated as SQLITE3_INTEGER, float as SQLITE3_FLOAT, null as SQLITE3_NULL and all others as SQLITE3_TEXT. Formerly, if type has been omitted, it has defaulted to SQLITE3_TEXT.

Note:

If value is null, it is always treated as SQLITE3_NULL, regardless of the given type.

返回值

Returns true if the value is bound to the statement variable, 或者在失败时返回 false.

更新日志

版本 说明
7.4.0 param now also supports the @param notation.

范例

Example #1 SQLite3Stmt::bindValue() example

<?php
$db 
= new SQLite3(':memory:');

$db->exec('CREATE TABLE foo (id INTEGER, bar STRING)');
$db->exec("INSERT INTO foo (id, bar) VALUES (1, 'This is a test')");

$stmt $db->prepare('SELECT bar FROM foo WHERE id=:id');
$stmt->bindValue(':id'1SQLITE3_INTEGER);

$result $stmt->execute();
var_dump($result->fetchArray(SQLITE3_ASSOC));
?>

以上例程会输出:

array(1) {
  ["bar"]=>
  string(14) "This is a test"
}

参见

User Contributed Notes

vaibhavatul47 at gmail dot com 13-Apr-2016 12:42
I used following logic to prepare statements, It handles both Values and Arrays ( taking help from bohwaz note) :

<?php
   
function getArgType($arg) {
        switch (
gettype($arg)) {
            case
'double':  return SQLITE3_FLOAT;
            case
'integer': return SQLITE3_INTEGER;
            case
'boolean': return SQLITE3_INTEGER;
            case
'NULL':    return SQLITE3_NULL;
            case
'string':  return SQLITE3_TEXT;
            default:
                throw new \
InvalidArgumentException('Argument is of invalid type '.gettype($arg));
        }
    }

foreach (
$params as $index => $val) {
               
// indexing start from 1 in Sqlite statement
               
if (is_array($val)) {
                   
$ok = $stmt->bindParam($index + 1, $val);
                } else {
                   
$ok = $stmt->bindValue($index + 1, $val, getArgType($val));
                }
               
                if (!
$ok) {
                    throw new
Exception("Unable to bind param: $val");
                }
            }
?>
andrevanzuydam at gmail dot com 06-Jul-2015 01:41
I just want to say again,

Numbering for parameters starts at ONE!

This has caught me out quite a few times!
bohwaz 18-Jan-2015 04:49
It might be a good idea to feed bindValue the type of the variable manually, or you might encounter weird stuff as the passed value is often treated as SQLITE3_TEXT and results in buggy queries.

For example:
<?php
$st
= $db->prepare('SELECT * FROM test WHERE (a+1) = ?');
$st->bindValue(1, 2);
?>

Will never return any result as it is treated by SQLite as if the query was 'SELECT * FROM test WHERE (a+1) = "2"'. Instead you have to set the type manually:

<?php
$st
= $db->prepare('SELECT * FROM test WHERE (a+1) = ?');
$st->bindValue(1, 2, \SQLITE3_INTEGER);
?>

And it will work. This bug is reported in https://bugs.php.net/bug.php?id=68849

Here is a simple function to help you make bindValue work correctly:

<?php
function getArgType($arg)
{
    switch (
gettype($arg))
    {
        case
'double': return SQLITE3_FLOAT;
        case
'integer': return SQLITE3_INTEGER;
        case
'boolean': return SQLITE3_INTEGER;
        case
'NULL': return SQLITE3_NULL;
        case
'string': return SQLITE3_TEXT;
        default:
            throw new \
InvalidArgumentException('Argument is of invalid type '.gettype($arg));
    }
}
?>
zeebinz at gmail dot com 23-Jul-2010 07:54
Note that this also works with positional placeholders using the '?' token:

<?php

$stmt
= $db->prepare('SELECT * FROM mytable WHERE foo = ? AND bar = ?');
$stmt->bindValue(1, 'somestring', SQLITE3_TEXT);
$stmt->bindValue(2, 42, SQLITE3_INTEGER);

?>

Positional numbering starts at 1.
PHP8中文手册 站长在线 整理 版权归PHP文档组所有